Can you solve it?
Edit: 500 replies!
Edit: How is this still going?!
Edit: oh God, the shitstorm is amazing
Edit: Aye! We're trending
Edit: 800!
Edit: 1000 AGHHGHH
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6÷2(1+2) 6÷2(3) 6÷6 1 Use PEMDAS
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Edited by Inflatablepants: 2/27/2016 7:50:13 PM
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People saying 1 make me fear for the future of earth. They are too damn stupid
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I don't think people realize you don't "choose" to multiply or divide first.... It's 9 you grape.
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It's one. -Donald trump
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Edited by bastage: 2/27/2016 7:41:24 PM9[b] [/b]
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9[b] [/b]
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Edited by SWilliams0507: 2/27/2016 6:47:13 PM9 or 1 depending on whether you multiply or divide first.
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Edited by brutekiller852: 2/27/2016 6:36:46 PM1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 I didn't want to put anymore Has to be one out of those twenty numbers
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The answer is Potato.
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Here is your pulse Here is your hand far from your pulse stuck up your own ass. Hi would you like a chocolate covered pretzel Awnser is = chocolate covered pretzel
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Edited by Ti84 plus: 2/27/2016 3:39:53 PM6/2(1+2) 6/2(3) Multiply the 2 with the 3 6/6 1. Pemdas It could also be this 6/2(1+2) 6/2(3) Divide 6 by 2 3(3) 9.
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1 Or 9 it depends, but usually you do multiplication first or you just go left to right with division a multiplication. If this was your homework, just try doing it yourself. Its just saying "I'm stupid, can you do this for me?"
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Edited by eternal_napalm: 2/27/2016 2:31:48 PM1. Order of operation PEMDAS
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9 following pemdas from left to right
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Lol it's 9 EZ PZ
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6/2(2+1) 6/2(3) 3(3) 9 What did I do wrong?
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It is 1
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9. [spoiler]wort[/spoiler]
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THREE WAYS to solve this question: 1st WAY: just forget about the PEMDAS or BODMAS rules, lets come back to the origin of mathematics which is solving human's problem: assumption: Have 6 apples, with 2 classes where combination of 2 boys & 1 girl. So, each of them get how many apple(s)?! thus, 2 classes , 2 boys & 1 gals = 3 students + 3 Students = total 6 students Now, only have 6 apples 6 apples for 6 students. Therefore, 1 student only have 1 apple = 1 (answer) 2nd Way: 6÷2(1+2) lets assume y =2 so that , 6÷y(1+y) = 6 ÷ (y+y^2) now replace 2 into y it shows 6 ÷ ( 2 + 2^2) = 6 ÷ (2 + 4) = 6 ÷ 6 = 1 (answer) 3rd way: 6÷2(1+2) lets assume (1+2) = a so that, 6÷2a now = 6/(2a) 2a is slightly different with 2 x a ; please dun tell me that is (6/2)x a !! lets simplify = 3/a now replace (1+2) into a = 3 (1+3) = 3/3 = 1 (answer) if you not agree again! fine lets go for the 4th way 4rth Way 6÷2(1+2) from this equation , we would say it has two group , A = 6 ; B = 2(1+2) lets 6÷2(1+2) = z so that, A/B = z A = zB 6 = z[2(1+ 2)] 6 = 6z z = 6/6 = 1 (answer)
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1 [b] [/b]
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Pemdas [spoiler]9[/spoiler]