{{
`${userDetail.user.displayName}${userDetail.user.cachedBungieGlobalDisplayNameCode ? `#${standardizeBungieGlobalCode(userDetail.user.cachedBungieGlobalDisplayNameCode)}` : ""}`}}
{{getUserClans()}}
3/2/2016 3:37:44 AM
8
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I haven't set any variables. It's impossible for you to derive that. psi^2=sin^2(n*pi/L*x) where x = 0.1 and L = 1 and N = 2
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Any chance psi^2 = 0.792 (3dp)? I haven't got a clue what "psi" is. I just did sin(2π/[1*0.1])^2 Square rooting that to find psi = 0.890 (3dp) If not, what would be the method to find the solution?
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I'm not sure if that's the correct answer, but I can if you normalize it. My program normalizes it. Normalize it in terms of 1, then get a percentage to work off. I can fact check that.
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Then 19
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Very, very wrong.
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I don't know how to do this type of math *flips table*
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Ok, I- [spoiler]head explodes[/spoiler]
