So there is a big building with lots of floors in a heavily populated city (new york or something, idk). And this building has a rooftop you can walk onto (like it has stairs leading to the rooftop).
So lets say there is a guy lying on the rooftop (thanks for those who answered that question) and another guy is standing next to him. They are both on the edge of the rooftop (thanks to Rudd for answering that question). Now the guy who is standing (joe) picks up the guy who is lying down (bob) and throws bob off the rooftop.
So how long would it take Bob to hit the ground? Obviously there is no way to be exact, just give a good estimate. Let's assume the building is like 15 stories high or something.
NOTE: building in picture is not to scale
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Okay the winner of this night's rooftop question is I heart Noobys. Maybe I should have made it a question thread so I can actually pick a winner. Thanks for your help everyone, all of these questions are really important. Tune in tomorrow night for another rooftop related question, folks.
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Edited by TheMANofCRIMSON: 11/9/2013 10:25:57 AMdo your own homework
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3.05 seconds (rounded at thousands place), neglecting air resistance. Here's my work.[quote]d=vi x t + 1/2at^2 (note that vi is initial velocity here) 45.72 = 0 + 1/2 x 9.8 x t^2 45.72 = 4.9t^2 9.3306 = t^2 Then take the root of both sides.[/quote]
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Edited by I Heart Noobies: 11/9/2013 7:44:30 AM[quote]According to my calculations, about 1.6 seconds.[/quote]
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Didn't read lol.
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Neglecting air resistance, Bob would reach about 100 feet per second, and if you want that in miles per hour it's about 68 mph, for a 15 story building.
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It depends what planet they're on.
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After the initial acceleration from the throw and fall (a dropped object does not immediately go to terminal velocity) Bob will accelerate 32 feet per second per second, until reaching terminal velocity (the speed at which an object's atmospheric drag counters the constant pull of Earth's gravitational force of 32 feet per second per second for a "constant" maximum speed, assuming the aerodynamics of the object don't change). The factors that go into determining an object's (ESPECIALLY if that object is A PERSON) individual terminal velocity requires a WHOLE LOT OF INFORMATION, including the person's shape and size... AND EVEN THEN, you'd have to come up with an average compiled from the various angles they could be falling at, as well as body position if you want one single number, which, again, will be an average of possible speeds, and is likely to be off a bit in either direction.
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CALL A SUICIDE HOTLINE IF YOURE THINKING OF ENDING IT ALL OP GOD BLESS
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Okay guys I drew a picture to help out. The building is not draw to scale though.
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4 seconds perhaps?
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well when you take the height of 15 stories, with the standard story stacking up to 12 ft 6 inches, you get 189 feet. You assume joe throws him with adequate strength making the train travel at a distance of 35 miles per hour. when you divide the apple by te potatoe you get 3 slices of pie. how many pieces of pizza did Bob get to eat?
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He'd fall at a rate at 9.8m/s/s or something until he reaches terminal velocity - which we don't know because we don't know the man's shape and size. so poo. Do your own homework.
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