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Okay, here's the problem:
Prove that the eigenfunctions for the infinite-well potential u_n(x) = sqrt(2/L)*sin(n*pi*x/L) have the property that...
the integral from 0 to L of u_n(x)*u_m(x)*dx = 0 for n=/=m
Please tell me someone on teh flodd is a Physics major.
English
#Offtopic
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Edited by HurtfulTurkey: 2/26/2014 3:16:32 AMBow before your Turkey Overlord. (Had to upload as a PDF because JPG made it too hard to read) You might want to show the integration; I just used wolframalpha for the individual ones because I'm rusty on the rules of integrating with cosine and sine.
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The Arbiter has your answer.."Were it so easy."
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Edited by HurtfulTurkey: 2/26/2014 3:16:51 AM-blam!- this. Edit: Okay gimme a sec. Convert that shit to cosine. ∫[sqrt(2/L)sin(n*pi*x/L)]*[sqrt(2/L)sin(m*pi*x/L)] dx from 0 to L = constant * ∫cos(bullshit that you can work out) - cos(bullshit but with -m) n=/=m, therefore: constant * integral of that shit = constant * L * [bullshit*sin + (negative bullshit)*sin(with -m) | from 0 to L =0 Whattuppp
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Why don't you ask Bill Nye? I'm going to guess the answer is yes.
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No replies? Thus is the power of Quantum Mechanics.